<?xml version='1.0' encoding='UTF-8'?><?xml-stylesheet href="http://www.blogger.com/styles/atom.css" type="text/css"?><feed xmlns='http://www.w3.org/2005/Atom' xmlns:openSearch='http://a9.com/-/spec/opensearchrss/1.0/'><id>tag:blogger.com,1999:blog-18322056.post2218499287467103632..comments</id><updated>2009-10-01T19:07:23.966-04:00</updated><title type='text'>Comments on Homeschool Math Blog: Understanding basic division</title><link rel='http://schemas.google.com/g/2005#feed' type='application/atom+xml' href='http://homeschoolmath.blogspot.com/feeds/2218499287467103632/comments/default'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/18322056/2218499287467103632/comments/default'/><link rel='alternate' type='text/html' href='http://homeschoolmath.blogspot.com/2009/09/understanding-basic-division.html'/><author><name>Maria Miller</name><uri>http://www.blogger.com/profile/00230743954246449727</uri><email>noreply@blogger.com</email></author><generator version='7.00' uri='http://www.blogger.com'>Blogger</generator><openSearch:totalResults>1</openSearch:totalResults><openSearch:startIndex>1</openSearch:startIndex><openSearch:itemsPerPage>25</openSearch:itemsPerPage><entry><id>tag:blogger.com,1999:blog-18322056.post-4639442195276807452</id><published>2009-10-01T18:13:05.105-04:00</published><updated>2009-10-01T18:13:05.105-04:00</updated><title type='text'>I think about it like this, 498 minus 6 would equa...</title><content type='html'>I think about it like this, 498 minus 6 would equate to one less &amp;#39;6&amp;#39;, and therefore be 82,  498 minus 6 is 492&lt;br /&gt;which is still too large, therefore we need to remove two 6&amp;#39;s and then add some, to get the result.&lt;br /&gt;Removing two sixes (or 12) leaves 486, now we need to add 5 to get back up to 491.&lt;br /&gt;&lt;br /&gt;Therefore the answer is 81 (83 - 2) remainder 5.&lt;br /&gt;&lt;br /&gt;I hope you see where I&amp;#39;m coming from.   &lt;br /&gt;&lt;br /&gt;Would you be able to review my &lt;a href="http://www.sumtree.com" rel="nofollow"&gt;Order of operations calculator&lt;/a&gt;, it shows a innovative way to do arithmetic.&lt;br /&gt;&lt;br /&gt;Thanks,&lt;br /&gt;Martin.</content><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/18322056/2218499287467103632/comments/default/4639442195276807452'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/18322056/2218499287467103632/comments/default/4639442195276807452'/><link rel='alternate' type='text/html' href='http://homeschoolmath.blogspot.com/2009/09/understanding-basic-division.html?showComment=1254435185105#c4639442195276807452' title=''/><author><name>marts</name><uri>http://www.blogger.com/profile/05876569905510337747</uri><email>noreply@blogger.com</email></author><thr:in-reply-to xmlns:thr='http://purl.org/syndication/thread/1.0' href='http://homeschoolmath.blogspot.com/2009/09/understanding-basic-division.html' ref='tag:blogger.com,1999:blog-18322056.post-2218499287467103632' source='http://www.blogger.com/feeds/18322056/posts/default/2218499287467103632' type='text/html'/></entry></feed>