This is the solution for the triangle problem with equal areas that I posted earlier. We are given that the areas of the three right triangles are equal, that is the area of the triangle DAE = area of the triangle EBF = area of the triangle FCD. We will make an equation based on that fact. For that, I like to use x as my variable, so I denote the longer side of the rectangle with a, the other side with b, the distance AE with x, and the distance BF with y. We are asked the ratio AE:EB, which is the same as x : (a − x) using my notation, and the ratio BF:FC, which is the same as y : (b − y) using my notation. The area of triangle ADE is its base times altitude divided by 2, or bx/2. The area of triangle EBF is its base times altitude divided by 2, or y(a − x)/2. The area of triangle CDF is its base times altitude divided by 2, or a(b − y)/2. And these three are equal. Basically you just make two equations from the above information, and manipulate your equations until y