And, we're asked to solve the RATIOS AE : EB and BF : FC.
The solution is here.
January 23, 2012
Triangle puzzle - equal areas
I hope Pat doesn't mind that I copied the image from his blog... He posted this triangle puzzle on his blog and I thought you might enjoy it, too!
Basically, we have a triangle DFE inside a rectangle, dividing the rectangle into various triangles. And, the three areas of fainter color are equal. That is, the area of the triangle DAE = area of the triangle EBF = area of the triangle FCD. (Notice the image is not drawn to scale at all.)
And, we're asked to solve the RATIOS AE : EB and BF : FC.
The solution is here.
And, we're asked to solve the RATIOS AE : EB and BF : FC.
The solution is here.
Subscribe to:
Post Comments (Atom)
2 comments:
Hey can you please tell us that we can use any method or have to apply some specific method like here we can go for exterior angle theorem.
Sorry - I forgot to pots the link to the solution - it's here now.
Post a Comment