A simple triangle problem
Someone sent in this very simple question (a student?).
A little bit of algebra helps in this problem.
FIRST strive to make a picture. Need a right triangle, the leg twice as long as the base. Here in my picture things aren't exactly to the scale, but it suffices for illustration purposes:
So we actually know that b = 2a.
The area of a triangle here is base times height over 2, and remember the height is the other leg, and it's twice the base:
area = ba/2 = (2a)(a)/2 , and this is 36 (given).
So we get our equation:
(2a)(a)/2 = 36
a2 = 36
a = 6.
The leg b is therefore 12 cm long. check: Legs are 12 and 6, so the area is 12 * 6 / 2 = 36.
Leg b of the right triangle is twice as long as the base a.
If the area is 36 cm squared, what is the length in of the leg b?
A little bit of algebra helps in this problem.
FIRST strive to make a picture. Need a right triangle, the leg twice as long as the base. Here in my picture things aren't exactly to the scale, but it suffices for illustration purposes:
So we actually know that b = 2a.
The area of a triangle here is base times height over 2, and remember the height is the other leg, and it's twice the base:
area = ba/2 = (2a)(a)/2 , and this is 36 (given).
So we get our equation:
(2a)(a)/2 = 36
a2 = 36
a = 6.
The leg b is therefore 12 cm long. check: Legs are 12 and 6, so the area is 12 * 6 / 2 = 36.
Comments
Yep. The legs are the other two sides of a right triangle, but not the hypotenuse.